2x^2+16x-70=14

Solution for 2x^2+16x-70=14 equation:

2x^2+16x-70=14

We move all terms to the left:

2x^2+16x-70-(14)=0

We add all the numbers together, and all the variables

2x^2+16x-84=0

a = 2; b = 16; c = -84;
Δ = b2-4ac
Δ = 162-4·2·(-84)
Δ = 928
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{928}=\sqrt{16*58}=\sqrt{16}*\sqrt{58}=4\sqrt{58}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(16)-4\sqrt{58}}{2*2}=\frac{-16-4\sqrt{58}}{4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(16)+4\sqrt{58}}{2*2}=\frac{-16+4\sqrt{58}}{4}
$